An electric iron of resistance 20 &Omega | Class 10 Science Chapter Electricity, Electricity NCERT Solutions

Question:

An electric iron of resistance 20 Ω takes a current of 5 A. Calculate the heat developed in 30 s.

Answer:

The amount of heat (H) produced is given by the joule’s law of heating as

H = VIt

Where,

Current, = 5 A

Time, t = 30 s

Voltage, = Current × Resistance = 5 × 20 = 100 V

H = 100 x 5 x 30 = 1.5x104 J

Therefore, the amount of heat developed in the electric iron is 1.5x104 J.


Study Tips for Answering NCERT Questions:

NCERT questions are designed to test your understanding of the concepts and theories discussed in the chapter. Here are some tips to help you answer NCERT questions effectively:

  • Read the question carefully and focus on the core concept being asked.
  • Reference examples and data from the chapter when answering questions about Electricity.
  • Review previous year question papers to get an idea of how such questions may be framed in exams.
  • Practice answering questions within the time limit to improve your speed and accuracy.
  • Discuss your answers with your teachers or peers to get feedback and improve your understanding.

Comments

Comment(s) on this Question

Welcome to the NCERT Solutions for Class 10 Science - Chapter . This page offers a step-by-step solution to the specific question from Excercise 6 , Question 3: An electric iron of resistance 20 Ω takes a current of 5 A. Calculate the heat developed in 30....