Two objects of masses 100 g and 200 g are moving along the same line and direction with velocities of 2 m s-1 and 1 m s-1, respectively. They collide and after the collision, the first object moves at a velocity of 1.67 m s-1. Determine the velocity of the second object.
Mass of one of the objects, m1 = 100 g = 100/1000 = 0.1 kg
Mass of the other object, m2 = 200 g = 200/1000 = 0.2 kg
Velocity of m1 before collision, v1 = 2 m/s
Velocity of m2 before collision, v2 = 1 m/s
Velocity of m1 after collision, v3 = 1.67 m/s
Velocity of m2 after collision = v4 = ?
By law of conservation of momentum :
Total momentum before collision = Total momentum after collision
m1v1 + m2v2 = m1v3 + m2v4
(0.1)2 + (0.2)1 = (0.1)1.67 + (0.2)v4
0.4 = 0.167 + 0.2v4
v4 = 1.165 m/s
The velocity of the second object after collision 1.165 m/s.
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Welcome to the NCERT Solutions for Class 9 Science - Chapter . This page offers a step-by-step solution to the specific question from Excercise 2 , Question 4: Two objects of masses 100 g and 200 g are moving along the same line and direction with velocities o....
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