How to Use NCERT Solutions Effectively
Learn the best strategies to make the most of NCERT solutions for your exam preparation.
Read MoreTwo objects of masses 100 g and 200 g are moving along the same line and direction with velocities of 2 m s-1 and 1 m s-1, respectively. They collide and after the collision, the first object moves at a velocity of 1.67 m s-1. Determine the velocity of the second object.
Mass of one of the objects, m1 = 100 g = 100/1000 = 0.1 kg
Mass of the other object, m2 = 200 g = 200/1000 = 0.2 kg
Velocity of m1 before collision, v1 = 2 m/s
Velocity of m2 before collision, v2 = 1 m/s
Velocity of m1 after collision, v3 = 1.67 m/s
Velocity of m2 after collision = v4 = ?
By law of conservation of momentum :
Total momentum before collision = Total momentum after collision
m1v1 + m2v2 = m1v3 + m2v4
(0.1)2 + (0.2)1 = (0.1)1.67 + (0.2)v4
0.4 = 0.167 + 0.2v4
v4 = 1.165 m/s
The velocity of the second object after collision 1.165 m/s.
NCERT questions are designed to test your understanding of the concepts and theories discussed in the chapter. Here are some tips to help you answer NCERT questions effectively:
This question is important because it tests key concepts from the NCERT syllabus and is frequently asked in CBSE exams.
This question is based on core NCERT concepts explained in the chapter and should be revised thoroughly before exams.
Step-by-step explanation:
• Mass of one of the objects, m1 = 100 g = 100/1000 = 0
• 1 kg
•
• Mass of the other object, m2 = 200 g = 200/1000 = 0
• 2 kg
Students often lose marks by skipping steps, writing incomplete explanations, or misunderstanding keywords used in the question.
Mass of one of the objects, m1 = 100 g = 100/1000 = 0.1 kg
Mass of the other object, m2 = 200 g = 200/1000 = 0.2 kg
Velocity of m1 before collision, v1 = 2 m/s
Velocity of m2 before collision, v2 = 1 m/s
...
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