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Class 10
Mathematics
Probability
a box contains 90 discs which are numbered from 1...

Question:
A box contains 90 discs which are numbered from 1 to 90. If one disc is drawn at random from the box, find the probability that it bears (i) a two-digit number (ii) a perfect square number (iii) a number divisible by 5.

Answer:

Total number of discs = 90

(i) A 2-digit number discs = 81

Probability of getting two-digit number = 81/90 = 9/10

(ii) A perfect square number disc = 9

Probability of getting a perfect square number disc

= 9/90 = 1/9

(iii) A number divisible by 5 = 18

Probability of getting numbered divisible by 5

= 18/90 = 1/5

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Question:
A box contains 90 discs which are numbered from 1 to 90. If one disc is drawn at random from the box, find the probability that it bears (i) a two-digit number (ii) a perfect square number (iii) a number divisible by 5.

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Question: A box contains 90 discs which are numbered from 1 to 90. If one disc is drawn at random from the box, find the probability that it bears (i) a two-digit number (ii) a perfect square number (iii) a number divisible by 5.

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Question:
A box contains 90 discs which are numbered from 1 to 90. If one disc is drawn at random from the box, find the probability that it bears (i) a two-digit number (ii) a perfect square number (iii) a number divisible by 5.