SELECT * FROM question_mgmt as q WHERE id=9803 AND status=1 SELECT id,question_no,question,chapter FROM question_mgmt as q WHERE courseId=9 AND subId=6 AND chapterId=282 and ex_no='2' AND status=1 ORDER BY CAST(question_no AS UNSIGNED) CBSE Free NCERT Solution of 10th mathematics Probability two customers shyam and ekta are visiting a partic

Question:

Two customers Shyam and Ekta are visiting a particular shop in the same week (Tuesday to Saturday). Each is equally likely to visit the shop on any day as on another day. What is the probability that both will visit the shop on (i) the same day? (ii) consecutive days? (iii) different days?

Answer:

Since the number of days on which they both visit is 5 (Tuesday, Wednesday, Thurday, Friday, Saturday) they both can visit in 5 ways.

Therefore, total no of possible outcomes 5×5 = 25

           (i)       When the both visits the same day

                     Total no of favourable outcomes = 5 (Tuesday, Tuesday)

                     (Wednesday, Wednesday) (Thursday,Thursday) (Friday, Friday) (Saturday, Saturday)

                     So,P(both visiting the same day) = 5/25 = 1/5

        (ii)        When they visits on consecutive days 8 (Tuesday, Wednesday)

                    (Wednesday, Thursday) (Thursday, Friday) (Friday, Saturday) (Saturday, Friday) (Friday, Thursday)

                     (Thursday, Wednesday)  and  (Wednesday, Tuesday) 

                   P (both visitng the consecutive days) = 8/25

      (iii)          when they visits the different days

                       P(E) = 1 – P (visits the Same day)

                    = 1 – 1/5 =4/5 


SELECT ex_no,question,question_no,id,chapter FROM question_mgmt as q WHERE courseId='9' AND subId='6' AND ex_no!=0 AND status=1 and id!=9803 ORDER BY views desc, last_viewed_on desc limit 0,10
SELECT ex_no,question,question_no,id,chapter FROM question_mgmt as q WHERE courseId='9' AND subId='6' AND ex_no!=0 AND status=1 and id!=9803 ORDER BY last_viewed_on desc limit 0,10
Q:

Comments

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  • 4 months ago

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  • Answered by Ekta Mehta
  • 4 months ago

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  • Answered by Ekta Mehta
  • 4 months ago

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