SELECT * FROM question_mgmt as q WHERE id=9806 AND status=1 SELECT id,question_no,question,chapter FROM question_mgmt as q WHERE courseId=9 AND subId=6 AND chapterId=282 and ex_no='2' AND status=1 ORDER BY CAST(question_no AS UNSIGNED)
A box contains 12 balls out of which x are black. If one ball is drawn at random from the box, what is the probability that it will be a black ball?
If 6 more black balls are put in the box, the probability of drawing a black ball is now double of what it was before. Find x.
Total no of balls = 12
Let the no. of black balls = x
P(E) of getting a black ball = [ x / 12]
(ii) When 6 more black balls added to bag
Total no of balls = 12 + 6 = 18
No of black balls = x + 6
P (black ball) = [(x + 6) / 18]
Acc. to question,
Before After
2 P(E)B = P(E)B
2 [x / 12] = [(x + 6) / 18]
x/6 = x + 6/18
x + 6 = 3x
2x = 6 => x =3
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