SELECT * FROM question_mgmt as q WHERE id=5152 AND status=1 SELECT id,question_no,question,chapter FROM question_mgmt as q WHERE courseId=9 AND subId=6 AND chapterId=268 and ex_no='2' AND status=1 ORDER BY CAST(question_no AS UNSIGNED) CBSE Free NCERT Solution of 10th mathematics Real Numbers given that hcf 306 657 9 find lcm 306 657

Question:

Given that HCF (306, 657) = 9, find LCM (306, 657).

Answer:

Given,
H.C.F (306, 657) = 9
First number (a) = 306
Second number (b) = 657
As we know, H.C.F × L.C.M = a × b
9 × L.C.M = 306 × 657
L.C.M = (306 × 657) / 9 = 22338
Hence, L.C.M (306, 657) = 22338


SELECT ex_no,question,question_no,id,chapter FROM question_mgmt as q WHERE courseId='9' AND subId='6' AND ex_no!=0 AND status=1 and id!=5152 ORDER BY views desc, last_viewed_on desc limit 0,10
SELECT ex_no,question,question_no,id,chapter FROM question_mgmt as q WHERE courseId='9' AND subId='6' AND ex_no!=0 AND status=1 and id!=5152 ORDER BY last_viewed_on desc limit 0,10
Q:

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  • 4 months ago

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  • 4 months ago

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  • Answered by Ekta Mehta
  • 4 months ago

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