SELECT * FROM question_mgmt as q WHERE id=996 AND status=1 SELECT id,question_no,question,chapter FROM question_mgmt as q WHERE courseId=2 AND subId=6 AND chapterId=80 and ex_no='1' AND status=1 ORDER BY CAST(question_no AS UNSIGNED)
\begin{align} a_n = \frac {n}{n+1}\end{align}
Substituting n = 1, 2, 3, 4, 5, we obtain
\begin{align} a_1 = \frac {1}{1+1}=\frac{1}{2},a_2 = \frac {2}{2+1}=\frac{2}{3},a_3 = \frac {3}{3+1}=\frac{3}{4},a_4 = \frac {4}{4+1}=\frac{4}{5},a_5 = \frac {5}{5+1}=\frac{5}{6}\end{align}
Therefore, the required terms are
\begin{align} \frac{1}{2},\frac{2}{3},\frac{3}{4},\frac{4}{5},and \frac{5}{6}\end{align}
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Report a problem on Specifications: