SELECT * FROM question_mgmt as q WHERE id=999 AND status=1 SELECT id,question_no,question,chapter FROM question_mgmt as q WHERE courseId=2 AND subId=6 AND chapterId=80 and ex_no='2' AND status=1 ORDER BY CAST(question_no AS UNSIGNED)
First term = 2
Let d be the common difference of the A.P.
Therefore, the A.P. is 2, 2 + d, 2 + 2d, 2 + 3d, …
Sum of first five terms = 10 + 10d
Sum of next five terms = 10 + 35d
According to the given condition,
\begin{align} => 10 + 10d = \frac{1}{4}(10 + 35d) \end{align}
\begin{align} => 40 + 40d = 10 + 35d \end{align}
\begin{align} => 30 = - 5d \end{align}
\begin{align} => d = - 6 \end{align}
\begin{align} \therefore a_{20} = a + (20 -1)d = 2 + (19)(-6) = 2 - 114 = -112\end{align}
Thus, the 20th term of the A.P. is –112.
Comments
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Report a problem on Specifications:
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Report a problem on Specifications: