SELECT * FROM question_mgmt as q WHERE id=3813 AND status=1 SELECT id,question_no,question,chapter FROM question_mgmt as q WHERE courseId=9 AND subId=16 AND chapterId=263 and ex_no='8' AND status=1 ORDER BY CAST(question_no AS UNSIGNED) CBSE Free NCERT Solution of 10th science Electricity two conducting wires of the same material and of e

Question:

Two conducting wires of the same material and of equal lengths and equal diameters are first connected in series and then parallel in a circuit across the same potential difference. The ratio of heat produced in series and parallel combinations would be –

(a) 1:2          (b) 2:1          (c) 1:4          (d) 4:1

Answer:

(c) The Joule heating is given by, H = i2Rt

Let, R be the resistance of the two wires.

The equivalent resistance of the series connection is RS = R + R = 2R

If V is the applied potential difference, then it is the voltage across the equivalent resistance.

The heat dissipated in time t is,

The equivalent resistance of the parallel connection is

 

V is the applied potential difference across this RP.

The heat dissipated in time t is,

So, the ratio of heat produced is,

Note: H   also H  i2 and H t. In this question, t is same for both the circuit. But the current through the equivalent resistance of both the circuit is different. We could have solved the question directly using H R if in case the current was also same. As we know the voltage and resistance of the circuits, we have calculated i in terms of voltage and resistance and used in the equation H = i2Rt to find the ratio.


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