SELECT * FROM question_mgmt as q WHERE id=3818 AND status=1 SELECT id,question_no,question,chapter FROM question_mgmt as q WHERE courseId=9 AND subId=16 AND chapterId=263 and ex_no='8' AND status=1 ORDER BY CAST(question_no AS UNSIGNED) CBSE Free NCERT Solution of 10th science Electricity a battery of 9 v is connected in series with resis

Question:

A battery of 9 V is connected in series with resistors of 0.2 Ω, 0.3 Ω, 0.4 Ω , 0.5 Ω and 12 Ω, respectively. How much current would flow through the 12 Ω resistor?

Answer:

There is no current division occurring in a series circuit. Current flow through the component is the same, given by Ohm’s law as

Where,

R is the equivalent resistance of resistances 0.2 Ω, 0.3 Ω, 0.4 Ω, 0.5 Ω and 12 Ω. These are connected in series. Hence, the sum of the resistances will give the value of R.

R = 0.2 + 0.3 + 0.4 + 0.5 + 12 = 13.4 Ω

Potential difference, V = 9 V

Therefore, the current that would flow through the 12 Ω resistor is 0.671 A.


SELECT ex_no,question,question_no,id,chapter FROM question_mgmt as q WHERE courseId='9' AND subId='16' AND ex_no!=0 AND status=1 and id!=3818 ORDER BY views desc, last_viewed_on desc limit 0,10
SELECT ex_no,question,question_no,id,chapter FROM question_mgmt as q WHERE courseId='9' AND subId='16' AND ex_no!=0 AND status=1 and id!=3818 ORDER BY last_viewed_on desc limit 0,10

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  • 4 months ago

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  • Answered by Ekta Mehta
  • 4 months ago

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  • Answered by Ekta Mehta
  • 4 months ago

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