SELECT * FROM question_mgmt as q WHERE id=3766 AND status=1 SELECT id,question_no,question,chapter FROM question_mgmt as q WHERE courseId=9 AND subId=16 AND chapterId=261 and ex_no='5' AND status=1 ORDER BY CAST(question_no AS UNSIGNED)
An object 5.0 cm in length is placed at a distance of 20 cm in front of a convex mirror of radius of curvature 30 cm. Find the position of the image, its nature and size.
Given,
Convex mirror
Radius of curvature, R = 30 cm
Radius of curvature = 2 × Focal length
R = 2f
f = 15 cm
Object distance, u = −20 cm
Object height, h = 5 cm
the mirror formula,
The value of v is positive which indicates that the image is formed behind the mirror.
The value of image height is positive which explains that the image formed is erect.
Hence, the image formed is virtual, erect, and smaller in size.
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