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Class 9
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Motion
a driver of a car travelling at 52 km h 1 nbsp app...

Question:
A driver of a car travelling at 52 km h^-1 applies the brakes and accelerates uniformly in the opposite direction. The car stops in 5 s. Another driver going at 3 km h^-1 in another car applies his brakes slowly and stops in 10 s. On the same graph paper, plot the speed versus time graphs for the two cars. Which of the two cars travelled farther after the brakes were applied?

Answer:

Case A:

Initial speed of the car, u₁ = 52 km/h = 52 x (5 / 18) = 14.44 m/s

Time taken, t₁ = 5 s

Final speed = 0 m/s

Case B:

Initial speed of the car, u₂ = 3 km/h = 3 x (5 / 18) = 0.833 m/s ≅ 0.83 m/s

Time taken, t₂ = 10 s

Final speed = 0 m/s

Plot of the two cars on a speed−time graph is shown in the following figure:

Distance covered by each car is equal to the area under the speed−time graph.

Distance covered in case A,

Distance covered in case B,

Then, the car1 travelling with a speed of 52 km/h travels farther after brakes were applied.

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