Electromagnetic Induction Question Answers: NCERT Class 12 Physics

Exercise 1
Q:
A:

Length of the rectangular wire, l = 8 cm = 0.08 m

Width of the rectangular wire, b = 2 cm = 0.02 m

Hence, area of the rectangular loop,

A = lb

= 0.08 × 0.02

= 16 × 10−4 m2

Magnetic field strength, B = 0.3 T

Velocity of the loop, v = 1 cm/s = 0.01 m/s

(a) Emf developed in the loop is given as:

e = Blv

= 0.3 × 0.08 × 0.01 = 2.4 × 10−4 V

Time taken to travel along the width , t = Distance traveled / Velocity = b / v

                                                                    =  0.02 / 0.01 = 2 s

Hence, the induced voltage is 2.4 × 10−4 V which lasts for 2 s.

(b) Emf developed, e = Bbv

= 0.3 × 0.02 × 0.01 = 0.6 × 10−4 V

Time taken to travel along the length, t = Distance traveled / Velocity = l / v
                                                                     =  0.08 / 0.01 = 8 s

Hence, the induced voltage is 0.6 × 10−4 V which lasts for 8 s.