On dividing x3 – 3x2 + x | Class 10 Mathematics Chapter Polynomials, Polynomials NCERT Solutions

Question:

On dividing x– 3x+ x + 2 by a polynomial g(x), the quotient and remainder were x – 2 nd –2x + 4, respectively. Find g(x).

Answer:

                   Given  ,

                   Dividend  p(x) =  x3 - 3x2 + x + 2

                   Quotient = x – 2

                   Remainder = -2x + 4

             Let divisor  = g(x)

             As we know ,

             Dividend = Divisor × Quotient + Remainder

                      x3- 3x2 +x+ 2 = g(x) × (x – 2) + (-2x + 4)

                      x 3- 3x2 + x + 2 – (-2x + 4) = g(x) × (x – 2 )

                     Therefore, g(x) × (x – 2 ) = x3 – x2 + x + 2

       Now we will divide p(x) by quotient x – 2 to find divisor g(x)

                                

            Therefore ,  g(x) = ( x2 – x + 1 )


Study Tips for Answering NCERT Questions:

NCERT questions are designed to test your understanding of the concepts and theories discussed in the chapter. Here are some tips to help you answer NCERT questions effectively:

  • Read the question carefully and focus on the core concept being asked.
  • Reference examples and data from the chapter when answering questions about Polynomials.
  • Review previous year question papers to get an idea of how such questions may be framed in exams.
  • Practice answering questions within the time limit to improve your speed and accuracy.
  • Discuss your answers with your teachers or peers to get feedback and improve your understanding.

Comments

Comment(s) on this Question

Welcome to the NCERT Solutions for Class 10 Mathematics - Chapter . This page offers a step-by-step solution to the specific question from Excercise 3 , Question 4: On dividing x3 – 3x2 + x + 2 by a polynomial g(x), the quotient and remainder were x....