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Find the sum to n terms in the geometric progression x3, x5,...

Find the sum to n terms in the | Class 11 Mathematics Chapter Sequence and Series, Sequence and Series NCERT Solutions

Question:

Find the sum to n terms in the geometric progression x³, x⁵, x⁷ ... (if x ≠ ±1)

Answer:

The given G.P. is x³, x⁵, x⁷ ........

Here, a = x³ and r = x²

^{$S subscript n space end subscript equals space fraction numerator a open parentheses 1 minus r to the power of n close parentheses over denominator 1 minus r end fraction equals fraction numerator x cubed open square brackets 1 minus open parentheses x squared close parentheses to the power of n close square brackets over denominator 1 minus x squared end fraction equals fraction numerator x cubed open parentheses 1 minus x to the power of 2 n end exponent close parentheses over denominator 1 minus x squared end fraction$}

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Read the question carefully and focus on the core concept being asked.
Reference examples and data from the chapter when answering questions about Sequence and Series.
Review previous year question papers to get an idea of how such questions may be framed in exams.
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Comments

Princy
2019-01-25 07:02:18

It is given in the question that x != 1 and x!= -1 ..so how can we use the formula for r1

Himani
2019-01-16 10:38:06

Same here. How can we assume here r is less than 1. It may be greater than one

Rajesh
2018-08-04 11:47:54

How r is less than 1?

umesh
2016-12-10 11:17:52

Sir how u assume r value less then 1 ,it may be greater then 1 also so that the sum of gp formula will different

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Welcome to the NCERT Solutions for Class 11 Mathematics - Chapter . This page offers a step-by-step solution to the specific question from Excercise 3 , Question 10: Find the sum to n terms in the geometric progression x3, x5, x7 ... (if x ≠ &....

Find the sum to n terms in the | Class 11 Mathematics Chapter Sequence and Series, Sequence and Series NCERT Solutions

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