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Find the sum to n terms in the geometric progression x3, x5,...

Find the sum to n terms in the | Class 11 Mathematics Chapter Sequence and Series, Sequence and Series NCERT Solutions

Question:

Find the sum to n terms in the geometric progression x³, x⁵, x⁷ ... (if x ≠ ±1)

Answer:

The given G.P. is x³, x⁵, x⁷ ........

Here, a = x³ and r = x²

^{$S subscript n space end subscript equals space fraction numerator a open parentheses 1 minus r to the power of n close parentheses over denominator 1 minus r end fraction equals fraction numerator x cubed open square brackets 1 minus open parentheses x squared close parentheses to the power of n close square brackets over denominator 1 minus x squared end fraction equals fraction numerator x cubed open parentheses 1 minus x to the power of 2 n end exponent close parentheses over denominator 1 minus x squared end fraction$}

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Comments

Princy
2019-01-25 07:02:18

It is given in the question that x != 1 and x!= -1 ..so how can we use the formula for r1

Himani
2019-01-16 10:38:06

Same here. How can we assume here r is less than 1. It may be greater than one

Rajesh
2018-08-04 11:47:54

How r is less than 1?

umesh
2016-12-10 11:17:52

Sir how u assume r value less then 1 ,it may be greater then 1 also so that the sum of gp formula will different

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Welcome to the NCERT Solutions for Class 11 Mathematics - Chapter . This page offers a step-by-step solution to the specific question from Excercise 3 , Question 10: Find the sum to n terms in the geometric progression x3, x5, x7 ... (if x ≠ &....

Find the sum to n terms in the | Class 11 Mathematics Chapter Sequence and Series, Sequence and Series NCERT Solutions

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