The sum of the first four terms of an A. | Class 11 Mathematics Chapter Sequence and Series, Sequence and Series NCERT Solutions

Q12.

The sum of the first four terms of an A.P. is 56. The sum of the last four terms is 112. If its first term is 11, then find the number of terms.

Let the A.P. be aa + da + 2da + 3d, ... a + (n – 2) da + (n – 1)d.

Sum of first four terms = a + (a + d) + (a + 2d) + (a + 3d) = 4a + 6d

Sum of last four terms = [a + (n – 4) d] + [a + (n – 3) d] + [a + (n – 2) d] + [a + n – 1) d] = 4a + (4n – 10) d

According to the given condition,

4a + 6d = 56

⇒ 4(11) + 6d = 56 [Since a = 11 (given)]

⇒ 6d = 12

⇒ d = 2

∴ 4a + (4n –10) d = 112

⇒ 4(11) + (4n – 10)2 = 112

⇒ (4n – 10)2 = 68

⇒ 4n – 10 = 34

⇒ 4n = 44

⇒ n = 11

Thus, the number of terms of the A.P. is 11.

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Why is this answer important for exams?

This question is important because it tests key concepts from the NCERT syllabus and is frequently asked in CBSE exams.

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What is the correct answer to: The sum of the first four terms of an A.P. is 56. The sum of the last four terms is 112. If its first term is 11, then find the number of terms.?

Let the A.P. be a, a + d, a + 2d, a + 3d, ... a + (n – 2) d, a + (n – 1)d.

Sum of first four terms = a + (a + ...

How do you solve The sum of the first four terms of an A.P. is 56. The sum of the last four terms is 112. If its first term is 11, then find the number of terms. step by step?

Step-by-step explanation:
• Let the A
• P
• be a, a + d, a + 2d, a + 3d,

What common mistakes should be avoided in this question?

Students often lose marks by skipping steps, writing incomplete explanations, or misunderstanding keywords used in the question.

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Student Discussion

Alan sajith
Class · · , · Jun 19, 2020
Gud job guys
well explained!!
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Faujdar
Class · · , · Nov 29, 2019
MST thank
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Faujdar
Class · · , · Nov 29, 2019
Mst
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Roya
Class · · , · Oct 08, 2019
Nice very helpful
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Tushar Giri
Class · · , · Sep 29, 2019
Thank you so much
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Mohan
Class · · , · Sep 19, 2019
Tu😍
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Tushar Gill
Class · · , · Jan 19, 2019
Thanks its very helpful
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Tushar Gill
Class · · , · Jan 19, 2019
Thanks its very helpful
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Mayank
Class · · , · Sep 05, 2018
Good
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Ishita Sharma
Class · · , · Aug 22, 2018
You have been doing a great job. Each step has been explainedc so well. I am really very much thankful to you
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