A three-wheeler starts from rest, accele | Class 11 Physics Chapter Motion in a straight Line, Motion in a straight Line NCERT Solutions

Question:

A three-wheeler starts from rest, accelerates uniformly with 1 m s–2 on a straight road for 10 s, and then moves with uniform velocity. Plot the distance covered by the vehicle during the nth second (n = 1,2,3….) versus n. What do you expect this plot to be during accelerated motion: a straight line or a parabola?

Answer:

Straight line

Distance covered by a body in nth second is given by the relation

Dn  =  u + a/2(2n-1)            .... (1)

u = Initial velocity

a = Acceleration

n = Time = 1, 2, 3, ..... ,n

In the given case,

u = 0 and a = 1 m/s2

∴ Dn  =  1/2(2n-1)               .... (2)

This relation shows that:

Dn ∝ n … (iii)

Now, substituting different values of n in equation (iii), we get the following table:

n 1 2 3 4 5 6 7 8 9 10
Dn 0.5 1.5 2.5 3.5 4.5 5.5 6.5 7.5 8.5 9.5

The plot between n and Dn will be a straight line as shown:

Since the given three-wheeler acquires uniform velocity after 10 s, the line will be parallel to the time-axis after n = 10 s.


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Welcome to the NCERT Solutions for Class 11 Physics - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 23: A three-wheeler starts from rest, accelerates uniformly with 1 m s–2 on a straight road for 10....