The ceiling of a long hall is 25 m high. What is the maximum horizontal distance that a ball thrown with a speed of 40 m s–1 can go without hitting the ceiling of the hall?
Speed of the ball, u = 40 m/s
Maximum height, h = 25 m
In projectile motion, the maximum height reached by a body projected at an angle θ, is given by the relation:
h = u2 sin2Ø / 2g
25 = 402 sin2Ø / 2 x 9.8
sin2 θ = 0.30625
sin θ = 0.5534
∴θ = sin–1(0.5534) = 33.60°
Horizontal range, R = u2 sin2Ø / g
= 402 x sin2 x 33.60 / 9.8
= 1600 x sin 67.2 / 9.8
= 1600 x 0.922 / 9.8 = 150.53 m
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Welcome to the NCERT Solutions for Class 11 Physics - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 15: The ceiling of a long hall is 25 m high. What is the maximum horizontal distance that a ball thrown ....
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