In problem 10.9, if 15.0 cm of water and spirit each are further poured into the respective arms of the tube, what is the difference in the levels of mercury in the two arms? (Specific gravity of mercury = 13.6)
Height of the water column, h1 = 10 + 15 = 25 cm
Height of the spirit column, h2 = 12.5 + 15 = 27.5 cm
Density of water, p1 = 1 g cm-3
Density of spirit, p2 = 0.8 g cm-3
Density of mercury = 13.6 g cm-3
Let h be the difference between the levels of mercury in the two arms.
Pressure exerted by height h, of the mercury column:
= hpg
= h × 13.6g … (i)
Difference between the pressures exerted by water and spirit:
= h1p1g
= g(25 × 1 - 27.5 × 0.8) = 3g … (ii)
Equating equations (i) and (ii), we get:
13.6 hg = 3g
h = 0.220588 ≈ 0.221 cm
Hence, the difference between the levels of mercury in the two arms is 0.221 cm.
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Welcome to the NCERT Solutions for Class 11 Physics - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 10: In problem 10.9, if 15.0 cm of water and spirit each are further poured into the respective arms of ....
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