• In changing the state of a gas adiabatically from an equilibrium state A to another equilibrium state B, an amount of work equal to 22.3 J is done on the system. If the gas is taken from state A to B via a process in which the net heat absorbed by the system is 9.35 cal, how much is the net work done by the system in the latter case? (Take 1 cal = 4.19 J)

  • In changing the state of a gas adiabatic | Class 11 Physics Chapter Thermodynamics, Thermodynamics NCERT Solutions

    Q5.

    In changing the state of a gas adiabatically from an equilibrium state A to another equilibrium state B, an amount of work equal to 22.3 J is done on the system. If the gas is taken from state A to B via a process in which the net heat absorbed by the system is 9.35 cal, how much is the net work done by the system in the latter case? (Take 1 cal = 4.19 J)

    The work done (W) on the system while the gas changes from state A to state B is 22.3 J.

    This is an adiabatic process. Hence, change in heat is zero.

    ∴ ΔQ = 0

    ΔW = -22.3 J (Since the work is done on the system)

    From the first law of thermodynamics, we have:

    ΔQ = ΔU + ΔW

    Where,

    ΔU = Change in the internal energy of the gas

    ∴ ΔU = ΔQ - ΔW = - (- 22.3 J)

    ΔU = + 22.3 J

    When the gas goes from state A to state B via a process, the net heat absorbed by the system is:

    ΔQ = 9.35 cal = 9.35 x 4.19 = 39.1765 J

    Heat absorbed, ΔQ = ΔU + ΔQ

    ∴ΔW = ΔQ - ΔU = 39.1765 - 22.3 = 16.8765 J

    Therefore, 16.88 J of work is done by the system.

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    What is the correct answer to: In changing the state of a gas adiabatically from an equilibrium state A to another equilibrium state B, an amount of work equal to 22.3 J is done on the system. If the gas is taken from state A to B via a process in which the net heat absorbed by the system is 9.35 cal, how much is the net work done by the system in the latter case? (Take 1 cal = 4.19 J)?

    The work done (W) on the system while the gas changes from state A to state B is 22.3 J.

    This is an adiabatic process. Hence, change in heat is zero.

    ∴ ΔQ = 0

    ΔW = -22.3 J (Since the work is d...

    How do you solve In changing the state of a gas adiabatically from an equilibrium state A to another equilibrium state B, an amount of work equal to 22.3 J is done on the system. If the gas is taken from state A to B via a process in which the net heat absorbed by the system is 9.35 cal, how much is the net work done by the system in the latter case? (Take 1 cal = 4.19 J) step by step?

    Step-by-step explanation:
    • The work done (W) on the system while the gas changes from state A to state B is 22
    • 3 J


    • This is an adiabatic process

    What common mistakes should be avoided in this question?

    Students often lose marks by skipping steps, writing incomplete explanations, or misunderstanding keywords used in the question.

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