• In changing the state of a gas adiabatically from an equilibrium state A to another equilibrium state B, an amount of work equal to 22.3 J is done on the system. If the gas is taken from state A to B via a process in which the net heat absorbed by the system is 9.35 cal, how much is the net work done by the system in the latter case? (Take 1 cal = 4.19 J)

  • In changing the state of a gas adiabatic | Class 11 Physics Chapter Thermodynamics, Thermodynamics NCERT Solutions

    Q5.

    In changing the state of a gas adiabatically from an equilibrium state A to another equilibrium state B, an amount of work equal to 22.3 J is done on the system. If the gas is taken from state A to B via a process in which the net heat absorbed by the system is 9.35 cal, how much is the net work done by the system in the latter case? (Take 1 cal = 4.19 J)

    The work done (W) on the system while the gas changes from state A to state B is 22.3 J.

    This is an adiabatic process. Hence, change in heat is zero.

    ∴ ΔQ = 0

    ΔW = -22.3 J (Since the work is done on the system)

    From the first law of thermodynamics, we have:

    ΔQ = ΔU + ΔW

    Where,

    ΔU = Change in the internal energy of the gas

    ∴ ΔU = ΔQ - ΔW = - (- 22.3 J)

    ΔU = + 22.3 J

    When the gas goes from state A to state B via a process, the net heat absorbed by the system is:

    ΔQ = 9.35 cal = 9.35 x 4.19 = 39.1765 J

    Heat absorbed, ΔQ = ΔU + ΔQ

    ∴ΔW = ΔQ - ΔU = 39.1765 - 22.3 = 16.8765 J

    Therefore, 16.88 J of work is done by the system.

    👍 0
    👎 0
    ✍️ Add Answer
    🚩 Report

    Study Tips for Answering NCERT Questions:

    NCERT questions are designed to test your understanding of the concepts and theories discussed in the chapter. Here are some tips to help you answer NCERT questions effectively:

    • Read the question carefully and focus on the core concept being asked.
    • Reference examples and data from the chapter when answering questions about Thermodynamics.
    • Review previous year question papers to get an idea of how such questions may be framed in exams.
    • Practice answering questions within the time limit to improve your speed and accuracy.
    • Discuss your answers with your teachers or peers to get feedback and improve your understanding.

    Important Questions & Answers

    Why is this answer important for exams?

    This question is important because it tests key concepts from the NCERT syllabus and is frequently asked in CBSE exams.

    Which NCERT concept is used in this question?

    This question is based on core NCERT concepts explained in the chapter and should be revised thoroughly before exams.

    What is the correct answer to: In changing the state of a gas adiabatically from an equilibrium state A to another equilibrium state B, an amount of work equal to 22.3 J is done on the system. If the gas is taken from state A to B via a process in which the net heat absorbed by the system is 9.35 cal, how much is the net work done by the system in the latter case? (Take 1 cal = 4.19 J)?

    The work done (W) on the system while the gas changes from state A to state B is 22.3 J.

    This is an adiabatic process. Hence, change in heat is zero.

    ∴ ΔQ = 0

    ΔW = -22.3 J (Since the work is d...

    How do you solve In changing the state of a gas adiabatically from an equilibrium state A to another equilibrium state B, an amount of work equal to 22.3 J is done on the system. If the gas is taken from state A to B via a process in which the net heat absorbed by the system is 9.35 cal, how much is the net work done by the system in the latter case? (Take 1 cal = 4.19 J) step by step?

    Step-by-step explanation:
    • The work done (W) on the system while the gas changes from state A to state B is 22
    • 3 J


    • This is an adiabatic process

    What common mistakes should be avoided in this question?

    Students often lose marks by skipping steps, writing incomplete explanations, or misunderstanding keywords used in the question.

    Latest Blog Posts

    Stay updated with our latest educational content and study tips

    Simple and Compound Interest Formulas with Questions

    Simple and Compound Interest Formulas with Questions

    Interest is one of the most significant ideas in maths and financial calculations. It is very common in banking, loan applications, investments, saving account and competitive exams. Simple Interest and Compound Interest make it easier to find out how much more is earned and/or paid on a principal during the period of time. These Interest … Read more

    Read More
    Spoken English Course Topics for Beginners in 2026

    Spoken English Course Topics for Beginners in 2026

    In 2026, students, professionals, and job seekers must have a high level of spoken English. Spoken English is a beginner level course to enhance learners’ communication skills in English, their pronunciation, vocabulary, grammar structure and confidence in speaking English fluently. Today, the emphasis of spoken English courses is placed on actual conversations, everyday speech practice … Read more

    Read More
    Difference Between AI and Machine Learning

    Difference Between AI and Machine Learning

    Artificial Intelligence (AI) and Machine Learning (ML) are two of the most sought-after technologies in today’s digital era. Although these terms are often used together, they are not the same. Machine Learning is, in fact, a component of Artificial Intelligence that enables systems to learn and enhance on their own, without direct programming. AI is … Read more

    Read More
    Time, Speed and Distance Formulas

    Time, Speed and Distance Formulas

    Time, Speed, and Distance are some of the most important concepts in mathematics and aptitude. These are the concepts which are used to calculate the speed of an object, time taken for an object to move and the distance traveled during the motion. Questions from this topic are frequently seen in School Tests, Competitive Tests, … Read more

    Read More

    Student Discussion

    Be the first to comment.

    ADD NEW COMMENT

          Can’t find your school? Type full name and submit.