Maximise Z = 3x + 4y Subject to the c | Class 12 Mathematics Chapter Linear Programming, Linear Programming NCERT Solutions

Question:

Maximise Z = 3x + 4y

Subject to the constraints:x + y ≤ 4, x ≥ 0, y ≥ 0

Answer:

The feasible region determined by the constraints, x + y ≤ 4, x ≥ 0, y ≥ 0, is as follows.

The corner points of the feasible region are O (0, 0), A (4, 0), and B (0, 4). The values of Z at these points are as follows.

Corner point

Z = 3x + 4y

 

O(0, 0)

0

 

A(4, 0)

12

 

B(0, 4)

16

→ Maximum

Therefore, the maximum value of Z is 16 at the point B (0, 4).


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Comments

  • Md Ammar
  • 2018-01-18 08:26:20

Thanku sir


Comment(s) on this Question

Welcome to the NCERT Solutions for Class 12 Mathematics - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 1: Maximise Z = 3x + 4y Subject to the constraints:x + y ≤ 4, x ≥ 0, y ≥ 0....