How to Use NCERT Solutions Effectively
Learn the best strategies to make the most of NCERT solutions for your exam preparation.
Read MoreA stone is dropped into a quiet lake and waves move in circles at the speed of 5 cm/s. At the instant when the radius of the circular wave is 8 cm, how fast is the enclosed area increasing?
The area of a circle (A) with radius (r) is given by A = πr2.
Therefore, the rate of change of area (A) with respect to time (t) is given by,
\begin{align} \frac{dA}{dt}=\frac{d}{dt}(\pi r^2)=\frac{d}{dt}(\pi r^2).\frac{dr}{dt}=2\pi r\frac{dr}{dt}\;\;\;[By\; Chain \;Rule]\end{align}
It is given that
\begin{align} \frac{dr}{dt}=5\; cm/s\end{align}
Thus, when r = 8 cm,
\begin{align} \frac{dA}{dt}=2\pi(8)(5)=80\pi\end{align}
Hence, when the radius of the circular wave is 8 cm, the enclosed area is increasing at the rate of 80π cm2/s.
NCERT questions are designed to test your understanding of the concepts and theories discussed in the chapter. Here are some tips to help you answer NCERT questions effectively:
The area of a circle (A) with radius (r) is given by A = πr2.
Therefore, the rate of change of area (A) with respect to time (t) is given by,
\begin{align} \frac{dA}{dt}=\frac{d}{dt}(\pi r^2)=\frac{d}{dt}(\pi r^...
Step-by-step explanation:
• The area of a circle (A) with radius (r) is given by A = πr2
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• Therefore, the rate of change of area (A) with respect to time (t) is given by,
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This question is important because it tests key concepts from the NCERT syllabus and is frequently asked in CBSE exams.
This question is based on core NCERT concepts explained in the chapter and should be revised thoroughly before exams.
Students often lose marks by skipping steps, writing incomplete explanations, or misunderstanding keywords used in the question.
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