SELECT * FROM question_mgmt as q WHERE id=1244 AND status=1 SELECT id,question_no,question,chapter FROM question_mgmt as q WHERE courseId=2 AND subId=9 AND chapterId=42 and ex_no='1' AND status=1 ORDER BY CAST(question_no AS UNSIGNED)
Calculate the molarity of a solution of ethanol in water in which the mole fraction of ethanol is 0.040 (assume the density of water to be one).
Mole fraction of C2H5OH= .................1
Let the moles of C2H5OH= X
Now density of water = 1 (given)
And the weight of 1000ml of water = volume * density (from density = mass/volume)
= 1000 x 1=1000g
Therefore moles of water = 1000/18= 55.55 mol (18g is molecular mass of water)
Also mole fraction of C2H5OH= 0.040 (given)
Putting the values in equation 1,we get
=0.040=X/X+55.55
=0.040X+2.222 = X
OR X= 2.3145 mol
Molarity of solution = 2.314 M
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