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Some Basic Concepts of Chemistry
which one of the following will have largest numbe...

Question:
Which one of the following will have largest number of atoms?

(i) 1 g Au (s)

(ii) 1 g Na (s)

(iii) 1 g Li (s)

(iv) 1 g of Cl2(g)

Answer:

(i) Gram atomic mass of Au= 197 g

197g of Au contains = 6.022 x 10²³

Therefore 1gm of Au contains = 6.022 x 10²³/197*1 = 3.06 x 10²¹ atoms

(ii) Gram atomic mass of Na = 23 g

23 g of Na contains atoms = 6.022x 10²³

1gm of Na contains atoms = 6.022x10²³ /23 *1 = 26.2 x10²¹ atoms

(iii) Gram atomic mass of Li = 7

7g of Li contains atoms = 6.022 x 10²³

1g of Li contains atoms = 6.022 x 10²³/7 *1= 86.0 x 10²¹ atoms

(iv) Gram atomic mass of Cl = 71 Or 71g of Cl contains atoms = 6.022x10²³

1 g of Cl contains atoms = 6.022x10²³ /71 * 1= 8.48 x 10²¹ atoms

Hence, 1 g of Li (s) will have the largest number of atoms.

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Question:
Which one of the following will have largest number of atoms?

(i) 1 g Au (s)

(ii) 1 g Na (s)

(iii) 1 g Li (s)

(iv) 1 g of Cl2(g)

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Question: Which one of the following will have largest number of atoms? (i) 1 g Au (s) (ii) 1 g Na (s) (iii) 1 g Li (s) (iv) 1 g of Cl2(g)

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Question:
Which one of the following will have largest number of atoms?

(i) 1 g Au (s)

(ii) 1 g Na (s)

(iii) 1 g Li (s)

(iv) 1 g of Cl2(g)