SELECT * FROM question_mgmt as q WHERE id=1256 AND status=1 SELECT id,question_no,question,chapter FROM question_mgmt as q WHERE courseId=2 AND subId=9 AND chapterId=43 and ex_no='1' AND status=1 ORDER BY CAST(question_no AS UNSIGNED)

Question:

Find energy of each of the photons which

(i) correspond to light of frequency 3× 1015 Hz.

(ii) have wavelength of 0.50 Å.

Answer:

Planck’s quantum theory = Based on the assumption that all atoms on the surface of the heated solid vibrate at the frequency, Planck developed a model that came to be known as Planck’s equation. Through experiments of frequencies and temperature, Planck was able to generate a constant, Planck’s constant

                                                           h = 6.62607 x 10-34 J s 

Using this constant he was able to restate his theory: energy was directly proportional to frequency. He wrote his equation as 

                                                          E=hν

where E is energy, h is Planck’s constant, and v is frequency.

(i) Energy (E) of a photon is given by the expression,

E=hν

Where, h = Planck’s constant = 6.626 × 10–34 Js

ν = frequency of light = 3 × 1015 Hz

Substituting the values in the given expression E = hv we get

E = (6.626 × 10–34) (3 × 1015)

E = 1.988 × 10–18 J

 

(ii) Energy (E) of a photon having wavelength (λ) is given by the expression,

 where , h = Planck’s constant = 6.626 × 10–34 Js

c = velocity of light in vacuum = 3 × 108 m/s

Substituting the values in the given expression of E:


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