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Class 12
Mathematics
Application of Derivatives
the total revenue in rupees received from the sale...

Question:
The total revenue in Rupees received from the sale of x units of a product is given by

R (x) = 3x² + 36x + 5. The marginal revenue, when x = 15 is

(A) 116 (B) 96 (C) 90 (D) 126

Answer:

Marginal revenue is the rate of change of total revenue with respect to the number of units sold.

\begin{align}MR=\frac{dR}{dx} \end{align}

∴Marginal Revenue (MR)= 3(2x) + 36 = 6x + 36

∴When x = 15,

MR = 6(15) + 36 = 90 + 36 = 126

Hence, the required marginal revenue is Rs 126.

The correct answer is D.

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Question:
The total revenue in Rupees received from the sale of x units of a product is given by

R (x) = 3x² + 36x + 5. The marginal revenue, when x = 15 is

(A) 116 (B) 96 (C) 90 (D) 126

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Question: The total revenue in Rupees received from the sale of x units of a product is given by R (x) = 3x2 + 36x + 5. The marginal revenue, when x = 15 is (A) 116 (B) 96 (C) 90 (D) 126

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Question:
The total revenue in Rupees received from the sale of x units of a product is given by

R (x) = 3x² + 36x + 5. The marginal revenue, when x = 15 is

(A) 116 (B) 96 (C) 90 (D) 126