SELECT * FROM question_mgmt as q WHERE id=1162 AND status=1 SELECT id,question_no,question,chapter FROM question_mgmt as q WHERE courseId=3 AND subId=6 AND chapterId=95 and ex_no='1' AND status=1 ORDER BY CAST(question_no AS UNSIGNED) CBSE Free NCERT Solution of 12th mathematics Application of Integrals find the area of the region bounded by the curve y

Question:

Find the area of the region bounded by the curve y2 = x and the lines x = 1, x = 4 and the x-axis.

Answer:

The area of the region bounded by the curve, y2 = x, the lines, x = 1 and x = 4, and the x-axis is the area ABCD.

\begin{align}Area \;of\; ABCD = \int_{1}^{4} y.dx \end{align}

 \begin{align} = \int_{1}^{4} \sqrt{x}.dx \end{align}

 \begin{align} =\left[\frac{x^\frac{3}{2}}{\frac{3}{2}}\right]_1^4 \end{align}

 \begin{align} =\frac{2}{3}\left[(4)^\frac{3}{2} - (1)^{\frac{3}{2}}\right] \end{align}

\begin{align} =\frac{2}{3}\left[8 -1\right] \end{align}

\begin{align} =\frac{14}{3}\; Units \end{align}


SELECT ex_no,question,question_no,id,chapter FROM question_mgmt as q WHERE courseId='3' AND subId='6' AND ex_no!=0 AND status=1 and id!=1162 ORDER BY views desc, last_viewed_on desc limit 0,10
SELECT ex_no,question,question_no,id,chapter FROM question_mgmt as q WHERE courseId='3' AND subId='6' AND ex_no!=0 AND status=1 and id!=1162 ORDER BY last_viewed_on desc limit 0,10

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