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Class 12
Mathematics
Differential Equations
determine order and degree if defined of differen...

Question:
Determine order and degree(if defined) of differential equation \begin{align}\left(\frac{ds}{dt}\right)^4\;+\;3s\frac{d^2s}{dt^2}\;=\;0\end{align}

Answer:

\begin{align}\left(\frac{ds}{dt}\right)^4\;+\;3s\frac{d^2s}{dt^2}\;=\;0\end{align}

The highest order derivative present in the given differential equation is\begin{align}\frac{d^2s}{dt^2}.\end{align}

Therefore, its order is two. It is a polynomial equation in

\begin{align}\frac{d^2s}{dt^2} and \frac{ds}{dt}.\end{align}

The power raised to is 1. \begin{align} \frac{d^2s}{dt^2} \end{align}

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Question:
Determine order and degree(if defined) of differential equation \begin{align}\left(\frac{ds}{dt}\right)^4\;+\;3s\frac{d^2s}{dt^2}\;=\;0\end{align}

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Question: Determine order and degree(if defined) of differential equation \begin{align}\left(\frac{ds}{dt}\right)^4\;+\;3s\frac{d^2s}{dt^2}\;=\;0\end{align}

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Question:
Determine order and degree(if defined) of differential equation \begin{align}\left(\frac{ds}{dt}\right)^4\;+\;3s\frac{d^2s}{dt^2}\;=\;0\end{align}