NCERT Solution
Class 12
Mathematics
Differential Equations
determine order and degree if defined of differen...

Question:
Determine order and degree(if defined) of differential equation \begin{align}\frac{d^2y}{dx^2}=\cos3x + sin3x\end{align}

Answer:

\begin{align}\frac{d^2y}{dx^2}=\cos3x + sin3x\end{align}

\begin{align}\Rightarrow\frac{d^2y}{dx^2} - \cos3x - sin3x = 0\end{align}

The highest order derivative present in the differential equation is\begin{align}\frac{d^2y}{dx^2}.\end{align}

Therefore, its order is two.It is a polynomial equation in \begin{align}\frac{d^2y}{dx^2}\end{align}

and the power raised to is 1.

\begin{align}\frac{d^2y}{dx^2}\end{align}

Hence, its degree is one.

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Question:
Determine order and degree(if defined) of differential equation \begin{align}\frac{d^2y}{dx^2}=\cos3x + sin3x\end{align}

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Question: Determine order and degree(if defined) of differential equation \begin{align}\frac{d^2y}{dx^2}=\cos3x + sin3x\end{align}

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Question:
Determine order and degree(if defined) of differential equation \begin{align}\frac{d^2y}{dx^2}=\cos3x + sin3x\end{align}