SELECT * FROM question_mgmt as q WHERE id=1154 AND status=1 SELECT id,question_no,question,chapter FROM question_mgmt as q WHERE courseId=3 AND subId=6 AND chapterId=96 and ex_no='2' AND status=1 ORDER BY CAST(question_no AS UNSIGNED) CBSE Free NCERT Solution of 12th mathematics Differential Equations y x2 nbsp 2x c nbsp nbsp y 39 nbsp 2x

Question:

y = x2 + 2x + C y' - 2x - 2 = 0   

Answer:

y = x2 + 2x + C

Differentiating both sides of this equation with respect to x, we get:

\begin{align}y^{'}=\frac{d}{dx}(x^2 + 2x + C)\end{align}

=> y' = 2x + 2

Substituting the value of y' in the given differential equation, we get:

L.H.S. = y' - 2x - 2 = 2x + 2 - 2x - 2 = 0 = R.H.S.

Hence, the given function is the solution of the corresponding differential equation.


SELECT ex_no,question,question_no,id,chapter FROM question_mgmt as q WHERE courseId='3' AND subId='6' AND ex_no!=0 AND status=1 and id!=1154 ORDER BY views desc, last_viewed_on desc limit 0,10
SELECT ex_no,question,question_no,id,chapter FROM question_mgmt as q WHERE courseId='3' AND subId='6' AND ex_no!=0 AND status=1 and id!=1154 ORDER BY last_viewed_on desc limit 0,10

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