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Question:

A short bar magnet has a magnetic moment of 0.48 J T-1. Give the direction and magnitude of the magnetic field produced by the magnet at a distance of 10 cm from the centre of the magnet on (a) the axis, (b) the equatorial lines (normal bisector) of the magnet.

Answer:

Magnetic moment of the bar magnet, M= 0.48 J T -1

(a) Distance, d = 10 cm = 0.1 m

The magnetic field at distance d, from the centre of the magnet on the axis is given by the relation:

 

Where,

μ0= Permeability of free space = 4π x 10-7  Tm A-1

The magnetic field is along the S - N direction.

(b) The magnetic field at a distance of 10 cm (i.e., d= 0.1 m) on the equatorial line of the magnet is given as:

The magnetic field is along the N - S direction.


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