SELECT * FROM question_mgmt as q WHERE id=3320 AND status=1 SELECT id,question_no,question,chapter FROM question_mgmt as q WHERE courseId=2 AND subId=8 AND chapterId=102 and ex_no='1' AND status=1 ORDER BY CAST(question_no AS UNSIGNED) CBSE Free NCERT Solution of 11th physics Motion in a straight Line a car moving along a straight highway with a speed

Question:

A car moving along a straight highway with a speed of 126 km h–1 is brought to a stop within a distance of 200 m. What is the retardation of the car (assumed uniform), and how long does it take for the car to stop?

Answer:

Initial velocity of the car, u = 126 km/h = 35 m/s

Final velocity of the car, v = 0

Distance covered by the car before coming to rest, s = 200 m

Retardation produced in the car = a

From third equation of motion, a can be calculated as:

v2 - u2 = 2as

(0)2 - (35)2   =  2 x a x 200

a  = -  (35 x 35)   /   (2  x  200)

a =  -3.06 m/s2

From first equation of motion, time (t) taken by the car to stop can be obtained as:

v = u + at

t  = v - u / a 

= -35 /  -3.06  =  11.44 s

 

 

 


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SELECT ex_no,question,question_no,id,chapter FROM question_mgmt as q WHERE courseId='2' AND subId='8' AND ex_no!=0 AND status=1 and id!=3320 ORDER BY last_viewed_on desc limit 0,10

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