SELECT * FROM question_mgmt as q WHERE id=3320 AND status=1 SELECT id,question_no,question,chapter FROM question_mgmt as q WHERE courseId=2 AND subId=8 AND chapterId=102 and ex_no='1' AND status=1 ORDER BY CAST(question_no AS UNSIGNED)
A car moving along a straight highway with a speed of 126 km h–1 is brought to a stop within a distance of 200 m. What is the retardation of the car (assumed uniform), and how long does it take for the car to stop?
Initial velocity of the car, u = 126 km/h = 35 m/s
Final velocity of the car, v = 0
Distance covered by the car before coming to rest, s = 200 m
Retardation produced in the car = a
From third equation of motion, a can be calculated as:
v2 - u2 = 2as
(0)2 - (35)2 = 2 x a x 200
a = - (35 x 35) / (2 x 200)
a = -3.06 m/s2
From first equation of motion, time (t) taken by the car to stop can be obtained as:
v = u + at
t = v - u / a
= -35 / -3.06 = 11.44 s
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