SELECT * FROM question_mgmt as q WHERE id=3450 AND status=1 SELECT id,question_no,question,chapter FROM question_mgmt as q WHERE courseId=2 AND subId=8 AND chapterId=114 and ex_no='1' AND status=1 ORDER BY CAST(question_no AS UNSIGNED) CBSE Free NCERT Solution of 11th physics Waves a transverse harmonic wave on a string is describe

Question:

A transverse harmonic wave on a string is described by

y(x,t)  =  3.0 sin [36t + 0.018x + π /4]

Where x and y are in cm and t in s. The positive direction of x is from left to right.

(a) Is this a travelling wave or a stationary wave? If it is travelling, what are the speed and direction of its propagation?

(b) What are its amplitude and frequency?

(c) What is the initial phase at the origin?

(d) What is the least distance between two successive crests in the wave?

Answer:

(a) Yes; Speed = 20 m/s, Direction = Right to left

(b) 3 cm; 5.73 Hz

(c) π /4

(d) 3.49 m

 

Explanation:

Given,

y(x, t) =3 sin (36t +0.018x + π/4) . . . . . . . . . . . ( 1 )

( i ) We know, the equation of a progressive wave travelling from right to left is:

y (x, t) = a sin (ωt + kx + Φ) . . . . . . . . . . . . . . . . . . . ( 2 )

Comparing equation ( 1 ) to equation ( 2 ), we see that it represents a wave travelling from right to left and also we get:

a = 3 cm, ω = 36 rad/s , k = 0.018 cm and ϕ = π/4

 

( ii )Therefore the speed of propagation , v = ω/k = 36/ 0.018 = 20 m/s

 

( iii ) Amplitude of the wave, a = 3 cm

Frequency of the wave v = ω / 2π = 36 /2π = 5.7 hz

 

( iv ) Initial phase at the origin = π/4

 

( v ) the smallest distance between two adjacent crests in the wave, λ = 2π/ k = 2π / 0.018 = 349 cm


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SELECT ex_no,question,question_no,id,chapter FROM question_mgmt as q WHERE courseId='2' AND subId='8' AND ex_no!=0 AND status=1 and id!=3450 ORDER BY last_viewed_on desc limit 0,10

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