SELECT * FROM question_mgmt as q WHERE id=3332 AND status=1 SELECT id,question_no,question,chapter FROM question_mgmt as q WHERE courseId=2 AND subId=8 AND chapterId=102 and ex_no='1' AND status=1 ORDER BY CAST(question_no AS UNSIGNED) CBSE Free NCERT Solution of 11th physics Motion in a straight Line the velocity time graph of a particle in one dimen

Question:

The velocity-time graph of a particle in one-dimensional motion is shown in Fig. 3.29:

Which of the following formulae are correct for describing the motion of the particle over the time-interval t2 to t1?

(a) x(t2) = x (t1) + v (t1) (t2–t1) + (1/2) a (t2–t1)2

(b) v(t2)= v(t1) + a(t2–t1)

(c) vAverage = (x(t2) – x (t1)) / (t2 – t1)

(d) aAverage = (v(t2) – v(t1)) / (t2 – t1)

(e) x(t2) = x(t1) + vAverage(t2 – t1) + ( 1/2 ) aAverage (t2–t1)2

(f) x(t2) – x(t1) = area under the v–t curve bounded by the t-axis and the dotted line shown.

Answer:

The correct formulae describing the motion of the particle are (c), (d) and, (f)

The given graph has a non-uniform slope. Hence, the formulae given in (a), (b), and (e) cannot describe the motion of the particle. Only relations given in (c), (d), and (f) are correct equations of motion.


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SELECT ex_no,question,question_no,id,chapter FROM question_mgmt as q WHERE courseId='2' AND subId='8' AND ex_no!=0 AND status=1 and id!=3332 ORDER BY last_viewed_on desc limit 0,10

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  • Answered by Ekta Mehta
  • 4 months ago

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