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the photograph of a house occupies an area of 1 75...

Question:
The photograph of a house occupies an area of 1.75 cm²on a 35 mm slide. The slide is projected on to a screen, and the area of the house on the screen is 1.55 m². What is the linear magnification of the projector-screen arrangement?

Answer:

Area of the house on the slide = 1.75 cm²

Area of the image of the house formed on the screen = 1.55 m²

= 1.55 × 10⁴ cm²

Arial magnification, m_a = Area of Image / Area of Object = (1.55 / 1.75) x 10⁴

∴Linear magnifications, m_l = underroot m_a

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Question:
The photograph of a house occupies an area of 1.75 cm²on a 35 mm slide. The slide is projected on to a screen, and the area of the house on the screen is 1.55 m². What is the linear magnification of the projector-screen arrangement?

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Question: The photograph of a house occupies an area of 1.75 cm2 on a 35 mm slide. The slide is projected on to a screen, and the area of the house on the screen is 1.55 m2. What is the linear magnification of the projector-screen arrangement?

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Question:
The photograph of a house occupies an area of 1.75 cm²on a 35 mm slide. The slide is projected on to a screen, and the area of the house on the screen is 1.55 m². What is the linear magnification of the projector-screen arrangement?