SELECT * FROM question_mgmt as q WHERE id=3316 AND status=1 SELECT id,question_no,question,chapter FROM question_mgmt as q WHERE courseId=2 AND subId=8 AND chapterId=101 and ex_no='1' AND status=1 ORDER BY CAST(question_no AS UNSIGNED)
Fill in the blanks
(a) The volume of a cube of side 1 cm is equal to.....m3
(b) The surface area of a solid cylinder of radius 2.0 cm and height 10.0 cm is equal to ... (mm)2
(c) A vehicle moving with a speed of 18 km h–1covers....m in 1 s
(d) The relative density of lead is 11.3. Its density is ....g cm–3 or . ...kg m–3.
a)
Length of edge = 1 cm Volume of the cube = 1 cm3 But, 1 cm3 = 1 cm × 1 cm × 1 cm = (1/100)m x (1/100)m x (1/100)m
∴1 cm3 = 10–6 m3 Hence, the volume of a cube of side 1 cm is equal to 10–6 m3.
(b) The total surface area of a cylinder of radius r and height h is S = 2πr (r + h).
Given that, r = 2 cm = 2 × 1 cm = 2 × 10 mm = 20 mm
h = 10 cm = 10 × 10 mm = 100 mm = 15072 = 1.5 × 104 mm2
(c) Using the conversion, 1 km/h = 5/18 m/s
18km/h = 18 x 5/18 = 5 m/s
Therefore, distance can be obtained using the relation:
Distance = Speed × Time
= 5 × 1 = 5 m
Hence, the vehicle covers 5 m in 1 s.
(d) Relative density of a substance is given by the relation,
Relative density = Density of Substance / Density of Water
Density of water = 1 g/cm3
Again, 1g = 1/1000 kg
1 cm3 = 10–6 m3
1 g/cm3 = 10-3 / 10-6 kg/m3 = 103 kg/m3
∴ 11.3 g/cm3 = 11.3 × 103 kg/m3
Comments
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Report a problem on Specifications: