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Class 9
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Force and Laws of Motion
a hockey ball of mass 200 g travelling at 10 m s 1...

Question:
A hockey ball of mass 200 g travelling at 10 m s^-1 is struck by a hockey stick so as to return it along its original path with a velocity at 5 m s^-1. Calculate the change of momentum occurred in the motion of the hockey ball by the force applied by the hockey stick.

Answer:

Mass of the hockey ball, m = 200 g = 200 / 1000 = 0.2 kg

Initial velocity, v₁ = 10 m/s

Initial momentum = mv₁

Final velocity, v₂ = −5 m/s

Final momentum = mv₂

Change in momentum = mv₁ − mv₂ = m(v₁ - v₂)

= 0.2 [10 − (−5)] = 0.2 (15) = 3.0 kg m/s

Hence, the change in momentum of the hockey ball is 3 kg m/s.

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Question:
A hockey ball of mass 200 g travelling at 10 m s^-1 is struck by a hockey stick so as to return it along its original path with a velocity at 5 m s^-1. Calculate the change of momentum occurred in the motion of the hockey ball by the force applied by the hockey stick.

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Question: A hockey ball of mass 200 g travelling at 10 m s-1 is struck by a hockey stick so as to return it along its original path with a velocity at 5 m s-1. Calculate the change of momentum occurred in the motion of the hockey ball by the force applied by the hockey stick.

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Question:
A hockey ball of mass 200 g travelling at 10 m s^-1 is struck by a hockey stick so as to return it along its original path with a velocity at 5 m s^-1. Calculate the change of momentum occurred in the motion of the hockey ball by the force applied by the hockey stick.