SELECT * FROM question_mgmt as q WHERE id=4096 AND status=1 SELECT id,question_no,question,chapter FROM question_mgmt as q WHERE courseId=8 AND subId=16 AND chapterId=187 and ex_no='1' AND status=1 ORDER BY CAST(question_no AS UNSIGNED) CBSE Free NCERT Solution of 9th science Motion a farmer moves along the boundary of a square fiel

Question:

A farmer moves along the boundary of a square field of side 10 m in 40 s. What will be the magnitude of displacement of the farmer at the end of 2 minutes 20 seconds?

Answer:

In fig. ABCD is a square field of side 10 m.

 

Time for one round = 40 s

Total time = 2 min 20 s

                = (2 x 60 + 20)s = 140s

Number of round completed =

                   

If farmer starts from A, it will complete 3 rounds (A → B → C → D → A) at A. In the last 0.5 round starting from A, he will finish at C. 

Displacement of farmer 


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