SELECT * FROM question_mgmt as q WHERE id=4111 AND status=1 SELECT id,question_no,question,chapter FROM question_mgmt as q WHERE courseId=8 AND subId=16 AND chapterId=187 and ex_no='5' AND status=1 ORDER BY CAST(question_no AS UNSIGNED) CBSE Free NCERT Solution of 9th science Motion a train is travelling at a speed of 90 km h 1 bra

Question:

A train is travelling at a speed of 90 km h-1. Brakes are applied so as to produce a uniform acceleration of – 0.5 m s-2. Find how far the train will go before it is brought to rest.

Answer:

Initial speed of the train, u = 90 km/h = 90 x 1000 / 60 x 60 = 25 m/s

Final speed of the train, v = 0 

Acceleration = −0.5 m s-2

Using equation of motion:

v2 = u2 + 2 as

(0)2 = (25)2 + 2 (−0.5) s

0 = 625 - s

 s = 625 m

Where, s is the distance covered by the train

The train will cover a distance of 625 m before it comes to rest.


SELECT ex_no,question,question_no,id,chapter FROM question_mgmt as q WHERE courseId='8' AND subId='16' AND ex_no!=0 AND status=1 and id!=4111 ORDER BY views desc, last_viewed_on desc limit 0,10
SELECT ex_no,question,question_no,id,chapter FROM question_mgmt as q WHERE courseId='8' AND subId='16' AND ex_no!=0 AND status=1 and id!=4111 ORDER BY last_viewed_on desc limit 0,10

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  • Answered by Ekta Mehta
  • 4 months ago

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