SELECT * FROM question_mgmt as q WHERE id=4111 AND status=1 SELECT id,question_no,question,chapter FROM question_mgmt as q WHERE courseId=8 AND subId=16 AND chapterId=187 and ex_no='5' AND status=1 ORDER BY CAST(question_no AS UNSIGNED)
A train is travelling at a speed of 90 km h-1. Brakes are applied so as to produce a uniform acceleration of – 0.5 m s-2. Find how far the train will go before it is brought to rest.
Initial speed of the train, u = 90 km/h = 90 x 1000 / 60 x 60 = 25 m/s
Final speed of the train, v = 0
Acceleration = −0.5 m s-2
Using equation of motion:
v2 = u2 + 2 as
(0)2 = (25)2 + 2 (−0.5) s
0 = 625 - s
s = 625 m
Where, s is the distance covered by the train
The train will cover a distance of 625 m before it comes to rest.
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