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Motion
a stone is thrown in a vertically upward direction...

Question:
A stone is thrown in a vertically upward direction with a velocity of 5 m s^-1. If the acceleration of the stone during its motion is 10 m s^-2 in the downward direction, what will be the height attained by the stone and how much time will it take to reach there?

Answer:

Initially, velocity of the stone,u = 5 m/s

Final velocity, v = 0

Acceleration of the stone, a = acceleration due to gravity, g = 10 m/s²

Since, u is upward & a is downward, it is a retarded motion.

Acceleration, a = −10 m/s²

Let s be the maximum height attained by the stone in time t.

According to the first equation of motion:

v = u + at

0 = 5 + (−10) t

According to the third equation of motion:

v² = u² + 2 as

(0)² = (5)² + 2(−10) s

However , the stone attains a height of 1.25 m in 0.5 s.

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Question:
A stone is thrown in a vertically upward direction with a velocity of 5 m s^-1. If the acceleration of the stone during its motion is 10 m s^-2 in the downward direction, what will be the height attained by the stone and how much time will it take to reach there?

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Question: A stone is thrown in a vertically upward direction with a velocity of 5 m s-1. If the acceleration of the stone during its motion is 10 m s-2 in the downward direction, what will be the height attained by the stone and how much time will it take to reach there?

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Question:
A stone is thrown in a vertically upward direction with a velocity of 5 m s^-1. If the acceleration of the stone during its motion is 10 m s^-2 in the downward direction, what will be the height attained by the stone and how much time will it take to reach there?