(i) 2x2 – 3x + 5 = 0
On comparing given equation ax2 + bx + c = 0
We get,
a = 2, b = -3 and c = 5
We know discriminant (D) = b2 – 4ac
D = (-3)2 – 4 2 5
D = 9 – 40
D = -31
As, b2 – 4ac < 0
Therefore, no real roots exist for the given equation.
(i) let x and y are the no of marbles of Romil and Somi respectively.
Acc. to ques,
X + y = 45................... (1)
When they both lost their 5 marbles
(x – 5) (y – 5) = 124.................... (2)
From equation (1), we have
y = 45 – x
Put this value of x in equation (2), we get
(x – 5)(45 – x – 5) = 124
(x – 5)(40 – x) = 124
40x – x2 – 200 + 5x = 128
x2 - 45x + 324 = 0
x2 - 36x - 9x + 324 = 0
x (x – 36) – 9 (x – 36) = 0
(x – 9) (x – 36) = 0
x = 9 or x = 36
Let the shorter side of rectangular field be = x meter
The diagonal of the field = (x + 60) m
And, longer side is 30m more than shorter side = (x + 30) m
According to question;
Using Pythagoras theorem;
(x + 60)2 = x2 + (x + 30)2
x (x - 90) + 30 (x - 90) = 0
(x + 30) (x - 90) = 0
(x + 30) = 0 or (x - 90) = 0
Either, x = -30 or x = 90
But x ≠ -30 because length can never be negative.
Hence, shorter side of field is 90 m and longer side is (x + 30) = 120 m