Quadratic Equations Question Answers: NCERT Class 10 Mathematics

Exercise 4
Q:
A:

(i)                 2x2 – 3x + 5 = 0

On comparing given equation ax2 + bx + c = 0

We get,

a = 2, b = -3 and c = 5

We know discriminant (D) = b2 – 4ac

D = (-3)2 – 4   2   5

D = 9 – 40

D = -31

As, b2 – 4ac < 0

Therefore, no real roots exist for the given equation.






Exercise 1
Q:

Exercise 2

Q:
A:

(i) let x and y are the no of marbles of Romil and Somi respectively.

Acc. to ques,

X + y = 45................... (1)

When they both lost their 5 marbles

(x – 5) (y – 5) = 124.................... (2)

From equation (1), we have

y = 45 – x

Put this value of x in equation (2), we get

(x – 5)(45 – x – 5) = 124

(x – 5)(40 – x) = 124

40x – x2 – 200 + 5x = 128

​x2 - 45x + 324 = 0

x2 - 36x - 9x + 324 = 0

x (x – 36) – 9 (x – 36) = 0

(x – 9) (x – 36) = 0

x = 9 or x = 36






Exercise 3
Q:






Q:
A:

Let the shorter side of rectangular field be = x meter

The diagonal of the field = (x + 60) m

And, longer side is 30m more than shorter side = (x + 30) m

According to question;

Using Pythagoras theorem;

(x + 60)2 = x2 + (x + 30)2

x (x - 90) + 30 (x - 90) = 0

(x + 30) (x - 90) = 0

(x + 30) = 0 or (x - 90) = 0

Either, x = -30 or x = 90

But x ≠ -30 because length can never be negative.

Hence, shorter side of field is 90 m and longer side is (x + 30) = 120 m