Let the resistance of an electrical component remains constant while the potential difference across the two ends of the component decreases to half of its former value. What change will occur in the current through it?
According to ohm's law we know that current is directly potential to the potential difference across the two ends.
V = IR
Here, R= Resistance of the electrical component
V= Potential difference and I=Current
The potential difference is reduced by half, keeping resistance constant.
Let the new resistance be R' and the new amount of current be I '.
Therefore, from Ohm’s law, we obtain the amount of new current.
So, the amount of current flowing through the electrical component is reduced by half.
You are given kerosene, turpentine and water. In which of these does the light travel fastest? Use the information given in Table 10.3.
| Material medium |
Refractive index |
Material medium |
Refractive index |
| Air | 1.0003 | Canada Balsam |
1.53 |
| Ice | 1.31 | ||
| Water | 1.33 | Rock salt | 1.54 |
| Alcohol | 1.36 | ||
| Kerosene | 1.44 | Carbon disulphide |
1.63 |
| Fused quartz |
1.46 | ||
| Turpentine oil |
1.47 | Ruby | 1.71 |
| Benzene | 1.50 | Sapphire | 1.77 |
| Crown glass |
1.52 | Diamond | 2.42 |
NCERT questions are designed to test your understanding of the concepts and theories discussed in the chapter. Here are some tips to help you answer NCERT questions effectively:
Welcome to the NCERT Solutions for Class 10 Science - Chapter . This page offers a step-by-step solution to the specific question from Excercise 3 , Question 3: Let the resistance of an electrical component remains constant while the potential difference across....
Comments