Welcome to the NCERT Solutions for Class 11 Mathematics - Chapter Sequence and Series. This page offers a step-by-step solution to the specific question from Exercise 5, Question 3: . With detailed answers and explanations for each chapter, students can strengthen their understanding and prepare confidently for exams. Ideal for CBSE and other board students, this resource will simplify your study experience.
Let the sum of n, 2n, 3n terms of an A.P. be S1, S2 and S3, respectively, show that S3 = 3 (S2– S1)
Let a and b be the first term and the common difference of the A.P. respectively.
Therefore,
From (1) and (2), we obtain
Hence, the given result is proved.
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Read MoreWelcome to the NCERT Solutions for Class 11 Mathematics - Chapter . This page offers a step-by-step solution to the specific question from Excercise 5 , Question 3: Let the sum of n, 2n, 3n terms of an A.P. be S1, S2 and S3, respectively, show t....
Comments
Awesome sir
What a nice answer it is!
how about if we solve this question like this... S1 = n S2 = n + 2n = 3n S3 = n + 2n + 3n = 6n according to question, S3 = 3(S2 -S1 ) by putting the value of S1, S2, S3 6n = 3(3n - n) 6n = 3(2n) 6n = 6n so, LHS = RHS Hence Proved