Estimate the fraction of molecular volum | Class 11 Physics Chapter Kinetic Theory, Kinetic Theory NCERT Solutions

Q1.

Estimate the fraction of molecular volume to the actual volume occupied by oxygen gas at STP. Take the diameter of an oxygen molecule to be 3Å.

Diameter of an oxygen molecule, d= 3Å

Radius, r = d /2 = 3/2 = 1.5 Å = 1.5 × 10-8 cm

Actual volume occupied by 1 mole of oxygen gas at STP = 22400 cm3

Molecular volume of oxygen gas, V  =  4/3 π r3 . N

Where, N is Avogadro's number = 6.023 × 1023 molecules/mole

∴  V  =  4/3 x 3.14 x (1.5 × 10-8 )x 6.023 × 1023

= 8.51 cm3

Ratio of the molecular volume to the actual volume of oxygen = 8.51 / 22400 =  3.8 × 10-4

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Important Questions & Answers

What is the correct answer to: Estimate the fraction of molecular volume to the actual volume occupied by oxygen gas at STP. Take the diameter of an oxygen molecule to be 3Å.?

Diameter of an oxygen molecule, d= 3Å

Radius, r = d /2 = 3/2 = 1.5 Å = 1.5 × 10-8 cm

Actual volume occupied by 1 mole of oxygen gas at STP = 22400 cm3

Molecular volume of oxygen gas, V&nbs...

How do you solve Estimate the fraction of molecular volume to the actual volume occupied by oxygen gas at STP. Take the diameter of an oxygen molecule to be 3Å. step by step?

Step-by-step explanation:
• Diameter of an oxygen molecule, d= 3Å

• Radius, r = d /2 = 3/2 = 1
• 5 Å = 1
• 5 × 10-8 cm

Why is this answer important for exams?

This question is important because it tests key concepts from the NCERT syllabus and is frequently asked in CBSE exams.

Which NCERT concept is used in this question?

This question is based on core NCERT concepts explained in the chapter and should be revised thoroughly before exams.

What common mistakes should be avoided in this question?

Students often lose marks by skipping steps, writing incomplete explanations, or misunderstanding keywords used in the question.

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