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Determine order and degree(if defined) of differential equation \...

Determine order and degree(if defined) o | Class 12 Mathematics Chapter Differential Equations, Differential Equations NCERT Solutions

Question:

Determine order and degree(if defined) of differential equation \begin{align}\left(\frac{ds}{dt}\right)^4\;+\;3s\frac{d^2s}{dt^2}\;=\;0\end{align}

Answer:

\begin{align}\left(\frac{ds}{dt}\right)^4\;+\;3s\frac{d^2s}{dt^2}\;=\;0\end{align}

The highest order derivative present in the given differential equation is\begin{align}\frac{d^2s}{dt^2}.\end{align}

Therefore, its order is two. It is a polynomial equation in

\begin{align}\frac{d^2s}{dt^2} and \frac{ds}{dt}.\end{align}

The power raised to is 1. \begin{align} \frac{d^2s}{dt^2} \end{align}

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Welcome to the NCERT Solutions for Class 12 Mathematics - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 3: Determine order and degree(if defined) of differential equation egin{align}left(frac{ds}{dt....

Determine order and degree(if defined) o | Class 12 Mathematics Chapter Differential Equations, Differential Equations NCERT Solutions

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