Determine order and degree(if defined) of differential equation \begin{align}\frac{d^2y}{dx^2}=\cos3x + sin3x\end{align}
\begin{align}\frac{d^2y}{dx^2}=\cos3x + sin3x\end{align}
\begin{align}\Rightarrow\frac{d^2y}{dx^2} - \cos3x - sin3x = 0\end{align}
The highest order derivative present in the differential equation is\begin{align}\frac{d^2y}{dx^2}.\end{align}
Therefore, its order is two.It is a polynomial equation in \begin{align}\frac{d^2y}{dx^2}\end{align}
and the power raised to is 1.
\begin{align}\frac{d^2y}{dx^2}\end{align}
Hence, its degree is one.
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Welcome to the NCERT Solutions for Class 12 Mathematics - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 5: Determine order and degree(if defined) of differential equation egin{align}frac{d^2y}{dx^2}=....
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