y = ex +1 : yn -y' = 0 | Class 12 Mathematics Chapter Differential Equations, Differential Equations NCERT Solutions

Question:

y = e^x +1 : yⁿ -y^' = 0

Answer:

y = e^x +1

Differentiating both sides of this equation with respect to x, we get:

\begin{align}\frac{dy}{dx}=\frac{d}{dx}(e^x + 1)\end{align}

=> y^' = e^x ...(1)

Now, differentiating equation (1) with respect to x, we get:

\begin{align}\frac{d}{dx}(y^{'})=\frac{d}{dx}(e^x)\end{align}

=> y^'' = e^x

Substituting the values of y^' and y^'' in the given differential equation, we get the L.H.S. as:

y^'' - y^' = e^x - e^x = 0 = R.H.S.

Thus, the given function is the solution of the corresponding differential equation.

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Welcome to the NCERT Solutions for Class 12 Mathematics - Chapter . This page offers a step-by-step solution to the specific question from Excercise 2 , Question 1: y = ex +1 : yn -y' = 0....

y = ex +1 : yn -y' = 0 | Class 12 Mathematics Chapter Differential Equations, Differential Equations NCERT Solutions

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