A farmer moves along the boundary of a s | Class 9 Science Chapter Motion, Motion NCERT Solutions

Question:

A farmer moves along the boundary of a square field of side 10 m in 40 s. What will be the magnitude of displacement of the farmer at the end of 2 minutes 20 seconds?

Answer:

In fig. ABCD is a square field of side 10 m.

 

Time for one round = 40 s

Total time = 2 min 20 s

                = (2 x 60 + 20)s = 140s

Number of round completed =

                   

If farmer starts from A, it will complete 3 rounds (A → B → C → D → A) at A. In the last 0.5 round starting from A, he will finish at C. 

Displacement of farmer 


Study Tips for Answering NCERT Questions:

NCERT questions are designed to test your understanding of the concepts and theories discussed in the chapter. Here are some tips to help you answer NCERT questions effectively:

  • Read the question carefully and focus on the core concept being asked.
  • Reference examples and data from the chapter when answering questions about Motion.
  • Review previous year question papers to get an idea of how such questions may be framed in exams.
  • Practice answering questions within the time limit to improve your speed and accuracy.
  • Discuss your answers with your teachers or peers to get feedback and improve your understanding.

Comments

Comment(s) on this Question

Welcome to the NCERT Solutions for Class 9 Science - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 2: A farmer moves along the boundary of a square field of side 10 m in 40 s. What will be the magnitude....