A train is travelling at a speed of 90 km h-1. Brakes are applied so as to produce a uniform acceleration of – 0.5 m s-2. Find how far the train will go before it is brought to rest.
Initial speed of the train, u = 90 km/h = 90 x 1000 / 60 x 60 = 25 m/s
Final speed of the train, v = 0
Acceleration = −0.5 m s-2
Using equation of motion:
v2 = u2 + 2 as
(0)2 = (25)2 + 2 (−0.5) s
0 = 625 - s
s = 625 m
Where, s is the distance covered by the train
The train will cover a distance of 625 m before it comes to rest.
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Welcome to the NCERT Solutions for Class 9 Science - Chapter . This page offers a step-by-step solution to the specific question from Excercise 5 , Question 2: A train is travelling at a speed of 90 km h-1. Brakes are applied so as to produce a uniform acceler....
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