A train is travelling at a speed of 90 k | Class 9 Science Chapter Motion, Motion NCERT Solutions

Question:

A train is travelling at a speed of 90 km h-1. Brakes are applied so as to produce a uniform acceleration of – 0.5 m s-2. Find how far the train will go before it is brought to rest.

Answer:

Initial speed of the train, u = 90 km/h = 90 x 1000 / 60 x 60 = 25 m/s

Final speed of the train, v = 0 

Acceleration = −0.5 m s-2

Using equation of motion:

v2 = u2 + 2 as

(0)2 = (25)2 + 2 (−0.5) s

0 = 625 - s

 s = 625 m

Where, s is the distance covered by the train

The train will cover a distance of 625 m before it comes to rest.


Study Tips for Answering NCERT Questions:

NCERT questions are designed to test your understanding of the concepts and theories discussed in the chapter. Here are some tips to help you answer NCERT questions effectively:

  • Read the question carefully and focus on the core concept being asked.
  • Reference examples and data from the chapter when answering questions about Motion.
  • Review previous year question papers to get an idea of how such questions may be framed in exams.
  • Practice answering questions within the time limit to improve your speed and accuracy.
  • Discuss your answers with your teachers or peers to get feedback and improve your understanding.

Comments

Comment(s) on this Question

Welcome to the NCERT Solutions for Class 9 Science - Chapter . This page offers a step-by-step solution to the specific question from Excercise 5 , Question 2: A train is travelling at a speed of 90 km h-1. Brakes are applied so as to produce a uniform acceler....