An object is dropped from rest at a height of 150 m and simultaneously another object is dropped from rest at a height 100 m. What is the difference in their heights after 2 s if both the objects drop with same accelerations? How does the difference in heights vary with time?
Initially, difference in heights of two objects
= 150 m – 100 m = 50 m
Distance travelled by first object in 2 s = h1
= 0 + ½ (2)2 = 2 g
Distance travelled by another object in 2 s = h2
= o + ½ (2)2 = 2 g
After 2 s, height at which the first object will be h1 = 150 - 2g
After 2 s, height at which the second object will be h2 = 100 - 2g
Thus, after 2 s, difference in height = 150 - 2g - (100 - 2g) = 50 m = initial difference in height.
Thus, the difference in height does not vary with time.
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Welcome to the NCERT Solutions for Class 9 Science - Chapter . This page offers a step-by-step solution to the specific question from Excercise 0 , Question 19: An object is dropped from rest at a height of 150 m and simultaneously another object is dropped fro....
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